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Writer's pictureSharon Rajendra Manmothe
Jun 198 min read

Ugc net paper 2024 answer key

The UGC NET Paper 2024 Answer Key is an essential resource for candidates aspiring to clear the National Eligibility Test (NET). This comprehensive guide provides accurate solutions to the questions asked in the UGC NET exam, helping candidates evaluate their performance. By analyzing the UGC NET Paper 2024 Answer Key, candidates can identify their strengths and areas needing improvement, ensuring better preparation for future attempts. Stay ahead in your exam preparation by utilizing the UGC NET Paper 2024 Answer Key to its fullest potential.


Question 51: Lower-triangular sparse matrix is one:

  1. in which all the non-zero elements lie only on the leading diagonal.

  2. in which all the non-zero elements lie above leading diagonal.

  3. in which all the non-zero elements lie below leading diagonal.

  4. which is not defined for sparse matrix.


Answer: 3. in which all the non-zero elements lie below leading diagonal.


Question 52: What will be the order of the following fields in a frame relay frame format?

A. FlagB. FCSC. AddressD. Information

Choose the correct answer from the options given below:

  1. A, C, D, B

  2. D, A, C, D

  3. C, B, A, D

  4. A, B, D, C

Answer: 1. A, C, D, B


Question 53: Which of the following are White box Testing?

A. Path TestingB. Loop TestingC. Regression TestingD. Non-functional Testing

Choose the correct answer from the options given below:

  1. A and B Only

  2. B and C Only

  3. C and D Only

  4. A and D Only

Answer: 1. A and B Only


Question 54: The techniques


Ugc net paper 2024 answer key
Ugc net paper 2024 answer key

used to handle the phantom problem are:

A. Time stampingB. Index lockingC. Predicate lockingD. Execution indexing

Choose the correct answer from the options given below:

  1. A and B Only

  2. B and C Only

  3. A and D Only

  4. C and D Only

Answer: 2. B and C Only


Question 57: Match List-I with List-II. f(n)=af(n/b)+g(n)f(n) = af(n/b) + g(n)f(n)=af(n/b)+g(n) is a divide-and-conquer recurrence relation for the algorithms listed in List-I. Match their recurrence in List-II.


List-I (Divide-and-conquer based algorithms) A. Binary SearchB. Find maximum and minimum of a sequenceC. Merge SortD. Fast Matrix Multiplication

List-II (Recurrence Relation)

  1. f(n)=7f(n/2)+15f(n) = 7f(n/2) + 15f(n)=7f(n/2)+15

  2. f(n)=f(n/2)+2f(n) = f(n/2) + 2f(n)=f(n/2)+2

  3. f(n)=2f(n/2)+nf(n) = 2f(n/2) + nf(n)=2f(n/2)+n

  4. f(n)=2f(n/2)+2f(n) = 2f(n/2) + 2f(n)=2f(n/2)+2

Choose the correct answer from the options given below:

  1. A-1, B-2, C-4, D-3

  2. A-2, B-4, C-1, D-3

  3. A-2, B-4, C-3, D-1

  4. A-2, B-3, C-4, D-1

Answer: 4. A-2, B-3, C-4, D-1


Question 58: Match List-I with List-II:

List-I A. Channelization protocolB. Bit-oriented protocolC. Random-access protocolD. Controlled-access protocol

List-II

  1. ALOHA

  2. TDMA

  3. Reservation

  4. HDLC

Choose the correct answer from the options given below:

  1. A-1, B-3, C-4, D-2

  2. A-2, B-4, C-1, D-3

  3. A-4, B-3, C-2, D-1

  4. A-3, B-4, C-1, D-2

Answer: 2. A-2, B-4, C-1, D-3


Question 59: An IPv4 packet has arrived with the first few hexadecimal digits as shown below. How many hops can this packet travel before being dropped? The data belong to what upper-layer protocol?

(540000 1800100110040601)

  1. 01 hops, TCP

  2. 02 hops, UDP

  3. 03 hops, ICMP

  4. 4 hops, TCP

Answer: Let's break down the IPv4 packet header:

  • The Time to Live (TTL) field is the 9th byte in the header.

  • "540000 1800100110040601" in hexadecimal, means the TTL field (18 in hex = 24 in decimal).

So, the packet can travel 24 hops before being dropped. Checking the protocol field, which is the 10th byte:

  • "06" (6 in hex) corresponds to TCP.

Thus, the correct interpretation:

None of the given options are correct according to the TTL value. However, if you want the closest option to what was intended:1. 01 hops, TCP (This might be a trick in the framing, ensure the actual digits are interpreted correctly in exam context.)


Question 60: Which of the following is the Markup language?

A. HTMLB. XMLC. DHTMLD. LMLE. PML

Choose the correct answer from the options given below:

  1. B, C, D Only

  2. A, C, D Only

  3. A, B, C Only

  4. A, C, E Only

Answer: 3. A, B, C Only

Question 61: Which of the following control problem does not exist, when processes are unaware of each other during interaction?

  1. Mutual exclusion

  2. Starvation

  3. Data coherence

  4. Deadlock

Answer: 3. Data coherence

Question 62: Arrange the following prefix expressions based on their values in increasing order:

A. + 2 / 8 4 3 2B. - 3 3 4 2 5C. + - 1 3 2 7 2 3 / 6 - 4 2D. * + 3 + 3 7 3 + 1 1 3

Choose the correct answer from the options given below:

  1. A, B, C, D

  2. B, A, C, D

  3. B, A, D, C

  4. C, D, A, B

Answer: Let's calculate the values of the prefix expressions:

A. + 2 / 8 4 3 2

  • Evaluate / 8 4 3: 8/(4+3)=8/7≈1.148 / (4 + 3) = 8 / 7 \approx 1.148/(4+3)=8/7≈1.14

  • 2 1.14: 2+1.14=3.142 + 1.14 = 3.142+1.14=3.14

B. - 3 3 4 2 5

  • Evaluate 3 3: 3∗3=93 3 = 93∗3=9

  • Evaluate 4 2: 4∗2=84 2 = 84∗2=8

  • Evaluate - 9 8 5: 9−(8+5)=9−13=−49 - (8 + 5) = 9 - 13 = -49−(8+5)=9−13=−4

C. + - 1 3 2 7 2 3 / 6 - 4 2

  • Evaluate - 1 3: 1−3=−21 - 3 = -21−3=−2

  • Evaluate 7 2 3: 723=77 2 3 = 7723=7

  • Evaluate / 6 - 4 2: 6/(4−2)=6/2=36 / (4 - 2) = 6 / 2 = 36/(4−2)=6/2=3

  • Evaluate + -2 7 3: −2+7+3=8-2 + 7 + 3 = 8−2+7+3=8

D. * + 3 + 3 7 3 + 1 1 3

  • Evaluate + 3 7: 3+7=103 + 7 = 103+7=10

  • Evaluate + 1 1: 1+1=21 + 1 = 21+1=2

  • Evaluate + 3 10 3: ∗310=3∗10=30 3 10 = 3 * 10 = 30∗310=3∗10=30

  • Evaluate * 30 2 3: 30+2+3=3530 + 2 + 3 = 3530+2+3=35

Based on these calculations, the order is:

  1. B: -4

  2. A: 3.14

  3. C: 8

  4. D: 35

Answer: 2. B, A, C, D


Question 63: Match List-I with List-II:

List-I (Line coding scheme) A. NRZ-LB. 2BIQC. 4-D-PAM5D. MLT-3

List-II (Bandwidth (average))

  1. B = N / 4

  2. B = N / 8

  3. B = N / 3

  4. B = N / 2

Choose the correct answer from the options given below:

  1. A-II, B-I, C-IV, D-III

  2. A-IV, B-I, C-II, D-III

  3. A-IV, B-I, C-III, D-II

  4. A-III, B-IV, C-II, D-I

Answer: 3. A-IV, B-I, C-III, D-II


Question 64: The instructions

ADD R1,A,BR_1, A, BR1​,A,BADD R2,C,DR_2, C, DR2​,C,DMUL X,R1,R2X, R_1, R_2X,R1​,R2​

Evaluate X=(A+B)∗(C+D)X = (A + B) * (C + D)X=(A+B)∗(C+D) in which of the following?

  1. 3-Address instructions

  2. 2-Address instructions

  3. 1-Address instructions

  4. RISC instructions

Answer: 1. 3-Address instructions


Question 65: For the fuzzy sets A={(x1,0.3),(x2,0.7),(x5,0.4)}A = \{ (x_1, 0.3), (x_2, 0.7), (x_5, 0.4) \}A={(x1​,0.3),(x2​,0.7),(x5​,0.4)} and B={(x1,0.5),(x2,0.2),(x3,0.5)}B = \{ (x_1, 0.5), (x_2, 0.2), (x_3, 0.5) \}B={(x1​,0.5),(x2​,0.2),(x3​,0.5)}, the fuzzy union A∪BA \cup BA∪B would be:

  1. {(x1,0.3),(x2,0.7),(x5,0.4)}\{ (x_1, 0.3), (x_2, 0.7), (x_5, 0.4) \}{(x1​,0.3),(x2​,0.7),(x5​,0.4)}

  2. {(x1,0.5),(x3,0.2),(x5,0.5)}\{ (x_1, 0.5), (x_3, 0.2), (x_5, 0.5) \}{(x1​,0.5),(x3​,0.2),(x5​,0.5)}

  3. {(x1,0.5),(x2,0.7),(x3,0.5)}\{ (x_1, 0.5), (x_2, 0.7), (x_3, 0.5) \}{(x1​,0.5),(x2​,0.7),(x3​,0.5)}

  4. {(x1,0.3),(x2,0.2),(x5,0.4)}\{ (x_1, 0.3), (x_2, 0.2), (x_5, 0.4) \}{(x1​,0.3),(x2​,0.2),(x5​,0.4)}

Answer: 3. {(x1,0.5),(x2,0.7),(x3,0.5)}\{ (x_1, 0.5), (x_2, 0.7), (x_3, 0.5) \}{(x1​,0.5),(x2​,0.7),(x3​,0.5)}


Question 66: Which of the following genetic algorithm operations is computationally most expensive?

  1. Convergence testing

  2. Initial population creation

  3. Selection of sub-population for mating

  4. Reproduction to produce the next generation

Answer: 4. Reproduction to produce the next generation


Question 67: Multiple Inheritance is permitted directly in:

A. C++B. JavaC. PythonD. VB.NETE. BASIC

Choose the most appropriate answer from the options given below:

  1. A and B Only

  2. A and C Only

  3. B and D Only

  4. A, C and E Only

Answer: 2. A and C Only


Question 68: The I/O methods in which memory addresses and I/O addresses are distinct, is called:

A. Isolated I/OB. Memory-Mapped I/OC. Strobe ControlD. HandshakingE. Interrupt

Choose the most appropriate answer from the options given below:

  1. A, B Only

  2. C, D Only

  3. C, E Only

  4. B, E Only

Answer: 1. A, B Only


Question 69: Which of the following is the function of the semantic analysis phase of the compilation process?

  1. Type conversion

  2. Tokenization

  3. Loop optimization

  4. Data flow analysis

Answer: 1. Type conversion


Question 70: IP is responsible for communication, while TCP is responsible for:

  1. Node-to-node, Host-to-host

  2. Process-to-process, Host-to-host

  3. Socket-to-socket, Host-to-node

  4. Host-to-Host, Process-to-process

Answer: 4. Host-to-Host, Process-to-process


Question 71: The Boolean expression for the following would be:

  1. AC + BC

  2. B + AC

  3. A + BC

Answer: 2. B + AC


Question 72: A computer system with cache access time of 100 ns, a main memory access time of 1100 ns, and a hit ratio of 0.9. The average access time would be:

  1. 200 ns

  2. 190 ns

  3. 210 ns

  4. 120 ns

Answer: To calculate the average access time: Average Access Time=(Cache Hit Ratio×Cache Access Time)+(Cache Miss Ratio×Main Memory Access Time)\text{Average Access Time} = (\text{Cache Hit Ratio} \times \text{Cache Access Time}) + (\text{Cache Miss Ratio} \times \text{Main Memory Access Time})Average Access Time=(Cache Hit Ratio×Cache Access Time)+(Cache Miss Ratio×Main Memory Access Time) =(0.9×100 ns)+(0.1×1100 ns)= (0.9 \times 100 \text{ ns}) + (0.1 \times 1100 \text{ ns})=(0.9×100 ns)+(0.1×1100 ns) =90 ns+110 ns= 90 \text{ ns} + 110 \text{ ns}=90 ns+110 ns =200 ns= 200 \text{ ns}=200 ns

1. 200 ns


Question 73: Services provided by point-to-point protocol (PPP):

A. Frame formatB. Establishment of the linkC. Flow controlD. Sequence numberingE. Authentication

Choose the correct answer from the options given below:

  1. A, B and E Only

  2. A, C and D Only

  3. D, E and B Only

  4. B, C and D Only

Answer: 1. A, B and E Only


Question 74: In Windows scheduling, which of the following options is correct?

  1. 4 non-real-time priorities

  2. 8 non-real-time priorities

  3. 12 non-real-time priorities

  4. 16 non-real-time priorities

Answer: 2. 8 non-real-time priorities


Question 75: Which of the following is/are true in case of tree locking?

A. It ensures shorter waiting times.B. It ensures freedom from deadlockC. Transaction can lock data items earlierD. It does not ensure greater amount of concurrency

Choose the correct answer from the options given below:

  1. A and B Only

  2. C and D Only

  3. B and C Only

  4. A and D Only


Answer: 3. B and C Only


Question 76: A least integer nnn such that f(x)f(x)f(x) is O(xn)O(x^n)O(xn) for each of the following functions. Arrange according to the value of nnn in increasing order:

A. f(x)=3x3+(log⁡(x))4f(x) = 3x^3 + (\log(x))^4f(x)=3x3+(log(x))4B. f(x)=x5+x2+1x3+1f(x) = \frac{x^5 + x^2 + 1}{x^3 + 1}f(x)=x3+1x5+x2+1​C. f(x)=x3+x2+1x2+1f(x) = \frac{x^3 + x^2 + 1}{x^2 + 1}f(x)=x2+1x3+x2+1​D. f(x)=x2+5⋅log⁡(x)x2+1f(x) = \frac{x^2 + 5 \cdot \log(x)}{x^2 + 1}f(x)=x2+1x2+5⋅log(x)​

  1. D, C, A, B

  2. D, C, B, A

  3. B, C, A, D

  4. B, A, C, D

Answer: 2. D, C, B, A

The correct order based on the increasing value of nnn:

  • D:f(x)=x2+5log⁡(x)x2+1D: f(x) = \frac{x^2 + 5 \log(x)}{x^2 + 1}D:f(x)=x2+1x2+5log(x)​ is O(1)O(1)O(1)

  • C:f(x)=x3+x2+1x2+1C: f(x) = \frac{x^3 + x^2 + 1}{x^2 + 1}C:f(x)=x2+1x3+x2+1​ is O(x)O(x)O(x)

  • A:f(x)=3x3+(log⁡(x))4A: f(x) = 3x^3 + (\log(x))^4A:f(x)=3x3+(log(x))4 is O(x3)O(x^3)O(x3)

  • B:f(x)=x5+x2+1x3+1B: f(x) = \frac{x^5 + x^2 + 1}{x^3 + 1}B:f(x)=x3+1x5+x2+1​ is O(x2)O(x^2)O(x2)

So, the increasing order is D,C,B,AD, C, B, AD,C,B,A.


Question 77: The language of the following PDA would be:

δ(q0,a,z0)=(q0,az0)δ(q0,a,a)=(q0,aa)δ(q0,b,a)=(q1,λ)δ(q1,b,a)=(q1,λ)δ(q1,ϵ,z0)=(qr,z0)where qr is a final state\delta(q_0, a, z_0) = (q_0, a z_0) \delta(q_0, a, a) = (q_0, a a) \delta(q_0, b, a) = (q_1, \lambda) \delta(q_1, b, a) = (q_1, \lambda) \delta(q_1, \epsilon, z_0) = (q_r, z_0) \quad \text{where } q_r \text{ is a final state}δ(q0​,a,z0​)=(q0​,az0​)δ(q0​,a,a)=(q0​,aa)δ(q0​,b,a)=(q1​,λ)δ(q1​,b,a)=(q1​,λ)δ(q1​,ϵ,z0​)=(qr​,z0​)where qr​ is a final state

Choose the correct language from the options given below:

  1. anbn∣n>0a^n b^n \mid n > 0anbn∣n>0

  2. anb2n∣n>0a^n b^{2n} \mid n > 0anb2n∣n>0

  3. anb3n∣n>0a^n b^{3n} \mid n > 0anb3n∣n>0

  4. anb4n∣n>0a^n b^{4n} \mid n > 0anb4n∣n>0

Answer: 1. anbn∣n>0a^n b^n \mid n > 0anbn∣n>0


Question 78: According to the Nyquist theorem, to produce the original analog signal, one necessary condition is:

  1. Sampling rate must be at least 2 times the highest frequency contained in the signal

  2. Sampling rate must be at least 2 times the lowest frequency contained in the signal

  3. Sampling rate must be at least 1/2 times the highest frequency contained in the signal

  4. Sampling rate must be at least 1/2 times the lowest frequency contained in the signal


Answer: 1. Sampling rate must be at least 2 times the highest frequency contained in the signal

Question 79: Match List I with List II.

List I (Boolean Expression) | List II (Dual of Boolean Expression)A. x(y+0)x(y + 0)x(y+0) | I. (x‾+0)(y‾z)(\overline{x} + 0)(\overline{y} z)(x+0)(y​z)B. x‾⋅1+(y‾+z)\overline{x} \cdot 1 + (\overline{y} + z)x⋅1+(y​+z) | II. x+y1x + y 1x+y1C. x‾(y‾+0)\overline{x} (\overline{y} + 0)x(y​+0) | III. x‾+y‾1\overline{x} + \overline{y} 1x+y​1D. x⋅1+(y+z‾)x \cdot 1 + (y + \overline{z})x⋅1+(y+z) | IV. (x+0)(y,z)(x + 0)(y, z)(x+0)(y,z)

Choose the correct answer from the options given below:

  1. A-III, B-IV, C-II, D-I

  2. A-III, B-IV, C-I, D-II

  3. A-II, B-I, C-III, D-IV

  4. A-II, B-I, C-IV, D-III


Answer: 3. A-II, B-I, C-III, D-IV

Question 80: The number of tokens in the following line for i in range (begin, end, step):

  1. 5

  2. 7

  3. 8

  4. 12

Answer: 3. 8


In conclusion, the UGC NET Paper 2024 Answer Key serves as a valuable tool for all candidates aiming to excel in the UGC NET exam. By thoroughly reviewing the UGC NET Paper 2024 Answer Key, candidates can gain insights into their performance, understand the correct answers, and refine their study strategies. Make the most of the UGC NET Paper 2024 Answer Key to enhance your preparation and increase your chances of success. Good luck with your UGC NET journey!

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